Wednesday, November 11, 2015
When Baire meets Krasner
Libellés :
algebraic geometry
,
Galois theory
,
topology
Here is a well-but-ought-to-be-better known theorem.
Theorem. — Let be a prime number and let be a compact subgroup of . Then there exists a finite extension of such that is contained in .
Before explaining its proof, let us recall why such a theorem can be of any interest at all. The keyword here is Galois representations.
It is now a well-established fact that linear representations are an extremly useful tool to study groups. This is standard for finite groups, for which complex linear representations appear at one point or another of graduate studies, and its topological version is even more classical for the abelian groups (Fourier series) and (Fourier integrals). On the other hand, some groups are extremly difficult to grasp while their representations are ubiquitous, namely the absolute Galois groups of fields .
With the notable exception of real closed fields, these groups are infinite and have a natural (profinite) topology with open subgroups the groups , where is a finite extension of lying in . It is therefore important to study their continuous linear representations. Complex representations are important but since is totally discontinuous, their image is always finite. Therefore, -adic representations, namely continuous morphisms from to , are more important. Here is the field of -adic numbers.
Their use goes back to Weil's proof of the Riemann hypothesis for curves over finite fields, via the action on -division points of its Jacobian variety. Here is a prime different from the characteristic of the ground field. More generally, every Abelian variety over a field of characteristic gives rise to a Tate module which is a free -module of rank , endowed with a continuous action of . Taking a basis of , one thus has a continuous morphism , and, embedding in the field of -adic numbers, a continuous morphism . Even more generally, one can consider the -adic étale cohomology of algebraic varieties over .
For various reasons, such as the need to diagonalize additional group actions, one can be led to consider similar representations where is replaced by a finite extension of , or even by the algebraic closure . Since is a compact topological groups, its image by a continuous representation is a compact subgroup of to which the above theorem applies.
This being said for the motivation, one proof (attributed to Warren Sinnott) is given by Keith Conrad in his short note, Compact subgroups of . In fact, while browsing at his large set of excellent expository notes, I fell on that one and felt urged to write this blog post.
The following proof had been explained to me by Jean-Benoît Bost almost exactly 20 years ago. I believe that it ought to be much more widely known.
It relies on the Baire category theorem and on Krasner's lemma.
Lemma 1 (essentially Baire). — Let be a compact topological group and let be an increasing sequence of closed subgroups of such that . There exists an integer such that .
Proof. Since is compact Hausdorff, it satisfies the Baire category theorem and there exists an integer such that contains a non-empty open subset . For every , then is an open neighborhood of identity contained in . This shows that is open in . Since is compact, it has finitely many cosets modulo ; there exists an integer such that for every , hence . QED.
Lemma 2 (essentially Krasner). — For every integer , the set of all extensions of of degree , contained in , is finite.
Proof. Every finite extension of has a primitive element whose minimal polynomial can be taken monic and with coefficients in ; its degree is the degree of the polynomial. On the other hand, Krasner's lemma asserts that for every such irreducible polynomial , there exist a real number for every monic polynomial such that the coefficients of have absolute values , then has a root in the field . By compactness of , the set of all finite subextensions of given degree of is finite. QED.
Let us now give the proof of the theorem. Let be a increasing sequence of finite subextensions of such that (lemma 2; take for the subfield generated by and all the subextensions of degree of ). Then is a closed subgroup of , and is the increasing union of all . By lemma 1, there exists an integer such that . QED.
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